Monday, May 29, 2006

M1 Problem for Monday

Here's an i and j vectors question to kick start your revision !!
(click the picture for a bigger version)


feel free to post your answers and I'll put my solutions up tomorrow with another problem.






Answers
a) diagram looks like this

so tanθ= 3/2

so θ=56.3º
so angle between direction of motion and j is 90+56.3 = 146º (3sf)

b) v = 2i - 3j + t (-i + 2j)
so v = (2-t) i + (2t - 3) j

c) when t=3
v = -i + 3j
so speed = IvI = sqroot( (-1)² + 3²) = 3.16 m/s²

d) when parallel to i, j component = 0
so 2t - 3 = 0 so t =1.5

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