M1 Problem for Monday
Here's an i and j vectors question to kick start your revision !!
(click the picture for a bigger version)
feel free to post your answers and I'll put my solutions up tomorrow with another problem.
a) diagram looks like this
so tanθ= 3/2
so angle between direction of motion and j is 90+56.3 = 146º (3sf)
b) v = 2i - 3j + t (-i + 2j)
so v = (2-t) i + (2t - 3) j
c) when t=3
v = -i + 3j
so speed = IvI = sqroot( (-1)² + 3²) = 3.16 m/s²
d) when parallel to i, j component = 0
so 2t - 3 = 0 so t =1.5