### M1 Problem for Monday

Here's an

**i**and

**j**vectors question to kick start your revision !!

(click the picture for a bigger version)

feel free to post your answers and I'll put my solutions up tomorrow with another problem.

**Answers**

a) diagram looks like this

so tanθ= 3/2

so θ=56.3º

so angle between direction of motion and

**j**is 90+56.3 = 146º (3sf)

b)

**v**= 2

**i**- 3

**j**+ t (-

**i**+ 2

**j**)

so

**v**= (2-t)

**i**+ (2t - 3)

**j**

c) when t=3

**v**= -

**i**+ 3

**j**

so speed = I

**v**I = sqroot( (-1)² + 3²) = 3.16 m/s²

d) when parallel to

**i, j**component = 0

so 2t - 3 = 0 so t =1.5

Labels: A Level, Exam Revision

## 0 Comments:

Post a Comment

## Links to this post:

Create a Link

<< Home